How to store values in matrix form for differn iteration
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ASHA PON
am 29 Jan. 2023
Kommentiert: Stephen23
am 29 Jan. 2023
I am having 7 decimal input data. This data varies for 500 iteration. Now, I need to store the 7 input data obtained in each iteration in a matrix form of 500*7. Thank you in advance.
For example:
A= [6 3 4 5 2 7 1]
Expected output:
[1 3 7 5 6 4 2 % iteration 1
2 4 7 6 5 3 1 % iteration 2
.
.
.
.
7 4 5 1 6 3 2 %iteration 500]
4 Kommentare
Dyuman Joshi
am 29 Jan. 2023
"Actually my requirement is, "
Then mention it clearly in the question. What your requirement is quite different from what your question asks.
"Now, I need to split this array into 500*7 matrix"
How do you want to split the array?
Akzeptierte Antwort
Dyuman Joshi
am 29 Jan. 2023
Use reshape()
%in case of row array
x=1:3500;
y=reshape(x,7,500)'
%in case of column array
a=(1:3500)';
b=reshape(a,7,500)'
1 Kommentar
Stephen23
am 29 Jan. 2023
To make the intent clear and avoid bugs, it is best to use actual transpose:
unless the complex conjugate transpose is specifically required:
Weitere Antworten (1)
Jan
am 29 Jan. 2023
Bearbeitet: Jan
am 29 Jan. 2023
A = [6 3 4 5 2 7 1];
Collected = zeros(500, 7);
for k = 1:500
A = rem(A + randi([0, 100], 1, 7), 10); % A random test function
Collected(k, :) = A;
end
" I am having an array stored with 3500 elemnts. Now, I need to split this array into 500*7 matrix.":
X = rand(1, 3500);
Y = reshape(X, 500, 7);
% Or:
Y = reshape(X, 7, 500).';
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