# Creating a row vector of combinations?

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Ali Almakhmari am 24 Jan. 2023
Kommentiert: Dyuman Joshi am 27 Jan. 2023
I have a row vector that 1 by 4. And I know that the minimum and maximum values of the elements in this vector to be -15 and 15. How can I make a matrix that is N by 4 that contains all possible combinations of ALL values?
Let me given an example: min = -15, max = 15, so the result of the code should be a matrix that is N by 4 that will look something like this
A = [[-15,0,0,0];[-14,0,0,0];[-13,0,0,0];[-12,0,0,0];[-11,0,0,0];[-10,0,0,0];[-9,0,0,0];....and so on until the final value vector to be[15,15,15,15]];
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### Akzeptierte Antwort

Davide Masiello am 24 Jan. 2023
You could use nchoosek. The example below is from -3 to 3 for memory issues (you'll generate a humongous matrix). Just substitute -15:15 and the trick is done.
A = nchoosek(-3:3,4)
A = 35×4
-3 -2 -1 0 -3 -2 -1 1 -3 -2 -1 2 -3 -2 -1 3 -3 -2 0 1 -3 -2 0 2 -3 -2 0 3 -3 -2 1 2 -3 -2 1 3 -3 -2 2 3
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Ali Almakhmari am 25 Jan. 2023
Thank you all for your help. You have been amazing!

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### Weitere Antworten (1)

Stephen23 am 25 Jan. 2023
but you will need plenty of memory:
V = -3:3
V = 1×7
-3 -2 -1 0 1 2 3
X = combinator(numel(V),4,'p','r');
M = V(X)
M = 2401×4
-3 -3 -3 -3 -3 -3 -3 -2 -3 -3 -3 -1 -3 -3 -3 0 -3 -3 -3 1 -3 -3 -3 2 -3 -3 -3 3 -3 -3 -2 -3 -3 -3 -2 -2 -3 -3 -2 -1
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Dyuman Joshi am 27 Jan. 2023
Okay, I'll try it. Thanks for replying.
Fair enough.

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