closest value to zero excluding the first one?

If given a long vector of values. How can I find the index of the closest value to zero excluding the first value of the vector out of our list of stuff to search for

[Ali Almakhmari]

I am attaching an example variable and the answer your code should result in should be 175 or the 174 index.

[Ali Almakhmari]

I = find(diff(dis_y>=0),1);

Answer 1

[Ali Almakhmari]

"dis_y" being the variable:

I = find(diff(dis_y>=0),1);

[Bruno Luong]

That is NOT your question asks for, that is first consecutive points where 0 is cross from positive to negative.

Answer 2

[Torsten]

out of our list of stuff to search for

?

v = [-0.1 2 4 -0.5 8];
[~,i] = min(abs(v(2:end)))

i = 3

v(i+1)

ans = -0.5000

[Image Analyst]

"out of our list of stuff to search for" <= He's searching FOR the index, so I think he really meant "out of our list of stuff to search", which is basically what @Torsten did. (No problem - non native English speakers probably don't know subtleties like that) The index would be

index = i+1;

[Ali Almakhmari]

hmm I dont think this works. For example, I attached this variable here. The answer to my question should be 175 or the 174 index. But with this code you have I do not get that.

[Ali Almakhmari]

Actually I found the solution: I = find(diff(dis_y>=0),1);

Answer 3

[Bora Eryilmaz]

load('var.mat')

[~,I] = sort(abs(dis_y), 'ascend');

% Closest value to 0:
dis_y(I(1))

ans = 2.3761e-05

% Second closest value to 0:
dis_y(I(2))

ans = -0.0014

[Ali Almakhmari]

This is still not giving me 175 or 174.

[Ali Almakhmari]

I = find(diff(dis_y>=0),1);