What is wrong in my code?
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q=readtable('a.txt');
A=q.a;
B=q.b;
C=q.c;
L=length(A);
P=length(B);
S=1;
q.complex=complex(q.d,q.e);
v=reshape(q.complex,L,[]);
X=-10.27:0.1361:10.139;
Y=-10.57:0.1401:10.4366;
v_I=16*ifft2(v.');
v_db=20*log10(v_I);
figure
imagesc(X,Y,v_db.'); grid on
axis equal
axis tight; colormap(hot);
My question is at theory wise v_I(i,j) has to be converted into v_I(e,f) where e=(i^2-j^2)/2*i and f=j and then we have to convert it into a figure. I am not able to this transform.
5 Kommentare
Benjamin Thompson
am 11 Jan. 2023
Please provide more information about what you are trying to do.
riki singh
am 11 Jan. 2023
Image Analyst
am 11 Jan. 2023
You need to define Yv_db, just like it says. Also, what variable is your image?
riki singh
am 11 Jan. 2023
riki singh
am 12 Jan. 2023
Antworten (1)
Hi @riki singh
I understand you're encountering an error when attempting to visualize a 2D complex-valued matrix using `imagesc`. The issue arises from passing complex data to a function that only supports real values.
In your code, you're performing an inverse FFT operation and then directly computing the dB scale with `log10`. You are applying `log10` directly to` v_I`, which is a complex matrix (since `ifft2` of complex data typically remains complex). Taking `log10` of complex values results in complex outputs, which `imagesc()` cannot plot.
To plot magnitude in dB, you should first take the absolute value of ` v_I`. Make the following changes in your code to compute `v_db`:
v_db = 20 * log10(abs(v_I) + eps);
I tried applying the above change, and ran the code with the given input file in MATLAB R2024b, and got the following plot:

Hope it helps.
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