In a loop, create an i x j matrix, find the average of each row, and find the minimum in which row.

Store matrix as i x j

store the difference between matrices m1 and m2 in m

After calculating the average value of each row of matrix m, which row has the minimum value is stored in k

m1 = [];
m2 = [];
% when img1 is up
for i = 1:5
    for j = 1:h2_t1
        st11H_t2 = st11H_t1(i:end,:,:);
        st22H_t2 = st22H_t1(1:end-i,:,:);
        p1 = impixel(st11H_t2, 1, j);
        m1 = [m1, p1];
        p2 = impixel(st22H_t2, w2_t1, j);
        m2 = [m2, p2];
    end
end
m1(~isfinite(m1))=0;
m2(~isfinite(m2))=0;

What should I do?

[Image Analyst]

Please give a numerical example of your matrix and your desired output, like

m = magic(5)

m = 5×5

17 24 1 8 15 23 5 7 14 16 4 6 13 20 22 10 12 19 21 3 11 18 25 2 9

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Answer 1

[DGM]

The answer is simple if you avoid the unnecessary loops.

inpict = uint8(randi([0 255],5,5)) % a 5x5 integer-class image

inpict = 5×5

111 109 89 67 118 129 139 165 13 148 207 32 78 47 61 51 127 171 203 147 205 176 60 254 205

rowmean = mean(inpict,2) % dim2 mean

rowmean = 5×1

98.8000 118.8000 85.0000 139.8000 180.0000

rowmin = min(inpict,[],2) % dim2 minima

rowmin = 5×1

67 13 32 51 60