"Error using /. Matrix Dimensions must agree." (Tried both / and ./)

3 Ansichten (letzte 30 Tage)
Luis
Luis am 16 Nov. 2022
Beantwortet: Navya Singam am 21 Nov. 2022
Not sure why I am getting this error. I read through the explanation that the Matlab helper gives you, but I am still confused. Here is my code so far:
>> d31=-320e-12;
>> Yp=62e9;
>> Yfca=250e9;
>> vp=0.5;
>>a=linspace(0,1);
>> d31eff=-d31./(log(1-a)*((1/a)-0.5))
Error using /
Matrix dimensions must agree.
I am very new to Matlab so any additional details are welcomed. Thank you!
  2 Kommentare
Stephen23
Stephen23 am 16 Nov. 2022
a has 100 elements. What do you expect 1/a to return? You need:
1./a
Torsten
Torsten am 16 Nov. 2022
d31eff = -d31 ./ ( log(1-a) .* (1./a - 0.5) )
instead of
d31eff=-d31./(log(1-a)*((1/a)-0.5))

Melden Sie sich an, um zu kommentieren.

Antworten (1)

Navya Singam
Navya Singam am 21 Nov. 2022
Hi Luis,
Changing this line of code wil resolve the issue.
d31eff=-d31./(log(1-a)*((1/a)-0.5))
to
d31eff=-d31./(log(1-a).*((1./a)-0.5));
You can refer to the following documenatations to understand more on the array operations and rdivide.

Kategorien

Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Produkte


Version

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by