I'm trying to create variable number of nested for loop depending on the length of vector. The length of each for loop depends on the number in that particular column of the vector. So for example:
if a = [2 3 3];
for i = 1:2
for j = 1:3
for k = 1:3
do something
end
end
end
I have looked around and it seems that recursive function is the best way to go about this. I know how to use a recursive function to replace a for loop but after that I'm not sure how to procede.
Here is a sample of my recursive code to replace a single for loop.
function result = h(x1)
% abc = 0;
if x1 <= 0
result = 1;
else
result = 2*h(x1-1);
end
Any help would be appreciated. Thanks!

1 Kommentar

Adam Danz
Adam Danz am 3 Apr. 2020
What's happening in do-something? If it's short, provide the code. If it's more than a dozen lines, a short description would due.

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 Akzeptierte Antwort

Sean de Wolski
Sean de Wolski am 23 Mär. 2015

0 Stimmen

I would just use two loops, one to loop over a and one to loop on each element of a:
a = [2 3 3];
for aloop = 1:numel(a)
for ii = 1:a(ii)
do whatever
end
end

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