how to add zeros in fronts of any number in matrix

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devendra
devendra am 22 Mär. 2015
Beantwortet: Jan am 22 Mär. 2015
dten = datenum([1998 1 1 ;2002 12 31]);
[M] = datevec(dten(1):dten(2));
years = M(:,1);
months = M(:,2);
days = M(:,3);
i want to add zeros in front of 1, 2, 3, 4, 5, 6, 7, 8, 9 like this 01, 02, 03, 04, 05, 06, 07, 08, 09 in months and days matrix. how will do this. please help me. thank you in advance.

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Konstantinos Sofos
Konstantinos Sofos am 22 Mär. 2015
Bearbeitet: Konstantinos Sofos am 22 Mär. 2015
Asking for this probably you do not want anymore your years, months, days vectors to be numbers but chars. Because you know from basic maths that '01' doesn't exist as type of number.
myCellMonth = cellfun(@(x) num2str(x),num2cell(months),'UniformOutput', false);
idx = cellfun(@(x) numel(x),myCellMonth);
idx = idx==1; % we want to add a leading '0' only in front of 1,2,3,...9
myCellMonth(idx) = cellfun(@(x) strcat('0', x),myCellMonth(idx),'UniformOutput', false)
In the same logic you could reform days and years
Regards
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Konstantinos Sofos
Konstantinos Sofos am 22 Mär. 2015
for the ' ' (inverted commas) use {} instead of () to read the context of a char cell array as i showed above. Hope that this helps.
devendra
devendra am 22 Mär. 2015
thank you so much Konstantinos Sofos for helping me.

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Jan
Jan am 22 Mär. 2015
sprintf and also num2str can use the '%02d' format:
myCellMonth = cellfun(@(x) num2str(x, '%02d'), num2cell(months),'UniformOutput', false);
This inserts a leading zero, when the number has less than 2 digits. Instead of preparing cell strings, you can use sprintf directly:
for i = 1:numel(M(:,1))
filename = sprintf('3B42_daily.%04d.%02d.%02d.7.SUB.nc', year(i), month(i), day(i));
...
end

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