How to find a specific row in the matrix and extract it to the new matrix
33 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Moe
am 2 Mär. 2015
Bearbeitet: Andrei Bobrov
am 2 Mär. 2015
Can anyone give me any suggestion how I can find the specific row (matrix= criteria) from main matrix (big matrix) and then extract to the some sub-matrices (A, B, C)
Z = [1 1 1 2
2 2 3 1
3 1 3 4
4 2 1 3
5 1 1 2
6 2 3 1
7 1 3 4
8 1 1 2
9 2 3 1
10 1 3 4
11 1 1 2
12 2 1 3
13 2 1 3
14 2 1 3
15 2 3 1
16 1 3 4
17 2 1 3
18 1 1 2
19 1 1 2
20 2 3 1
21 2 3 1
22 1 3 4
23 1 1 2
24 2 1 3
25 2 1 3
26 2 3 1
27 1 3 4]
M = [1 1 2
2 3 1
1 3 4]
2 Kommentare
Akzeptierte Antwort
Andrei Bobrov
am 2 Mär. 2015
Bearbeitet: Andrei Bobrov
am 2 Mär. 2015
Z = [1 1 1 2
2 2 3 1
3 1 3 4
4 2 1 3
5 1 1 2
6 2 3 1
7 1 3 4
8 1 1 2
9 2 3 1
10 1 3 4
11 1 1 2
12 2 1 3
13 2 1 3
14 2 1 3
15 2 3 1
16 1 3 4
17 2 1 3
18 1 1 2
19 1 1 2
20 2 3 1
21 2 3 1
22 1 3 4
23 1 1 2
24 2 1 3
25 2 1 3
26 2 3 1
27 1 3 4];
M = [1 1 2
2 3 1
1 3 4];
[l,i0] = ismember(Z(:,2:end),M,'rows');
zz = Z(l,:);
out = accumarray(i0(l),(1:nnz(i0))',[],@(x){sortrows(zz(x,:))});
0 Kommentare
Weitere Antworten (2)
Guillaume
am 2 Mär. 2015
ismatchrow = ismember(Z(:, 2:end), M(1, :), 'rows');
A = Z(ismatchrow, :)
Or to obtain a cell array with all the submatrices:
[~, matchrow] = ismember(Z(:, 2:end), M, 'rows');
matches = cell(1, max(matchrow));
for m = 1:max(matchrow)
matches{m} = Z(matchrow == m, :);
end
celldisp(matches)
0 Kommentare
Star Strider
am 2 Mär. 2015
This works:
[Zu, ia, ic] = unique(Z(:,2:4), 'rows');
[Lia,Locb] = ismember(M,Zu,'rows');
for k1 = 1:size(M,1)
R{k1} = find(Locb(k1) == ic);
end
A = Z(R{1},:);
B = Z(R{2},:);
C = Z(R{3},:);
0 Kommentare
Siehe auch
Kategorien
Mehr zu Cell Arrays finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!