Fitting Data to a Square root Cruve
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I'm looking to fit some data that I have to a function in the form of
y=k(sqrt(x))
with "k" being some constant. How would I find such a line of best fit for the data that I have?
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Matt J
am 6 Sep. 2022
k=sqrt(x(:))\y(:)
5 Kommentare
Image Analyst
am 6 Sep. 2022
fontSize = 18;
spacing=[0.5,1,1.5,2,2.5,3];
velocity=[55.71428571,72.97297297,88.46153846,100,115.1162791,116.3265306];
coefficients = sqrt(spacing(:))\velocity(:);
fittedVelocity = coefficients*(sqrt(spacing))
subplot(2, 1, 1);
plot(spacing, velocity, 'rv', spacing, fittedVelocity,'b.-') ;
grid on;
title('Velocity Measurements', 'FontSize', fontSize)
xlabel('Spacing', 'FontSize', fontSize)
ylabel('Velocity', 'FontSize', fontSize)
legend('Original Data', 'Fitted Curve', 'Location', 'northwest')
% Determine and say how well we did with our predictions, numerically, using several metrics like RMSE and MAE.
% Fit a linear model between predicted and true so we can get the R squared.
subplot(2, 1, 2);
% Draw 45 degree line.
line([50, 120], [50, 120], 'Color', 'g', 'LineWidth', 2)
hold on;
plot(velocity, fittedVelocity, 'b.-', 'LineWidth', 2, 'MarkerSize', 25);
grid on;
xlabel('Velocity (Original Data)', 'FontSize', fontSize)
ylabel('Fitted Velocity', 'FontSize', fontSize)
mdl = fitlm(velocity, fittedVelocity);
rSquared = mdl.Rsquared.Ordinary;
caption = sprintf('R Squared = %.3f', rSquared);
title(caption, 'FontSize', fontSize, 'Interpreter', 'none')
legend('Perfect Fit Line', 'Fitted vs. Original Data', 'Location', 'northwest')
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