How to rearrange columns in a MATRIX?

19 Ansichten (letzte 30 Tage)
Leeba Ann Chacko
Leeba Ann Chacko am 4 Sep. 2022
Verschoben: Walter Roberson am 5 Sep. 2022
I have a 2x4 matrix 'X' which looks like the follwing
X = 17.0600 29.6780 23.0660 29.4160
19.0280 42.3270 22.7940 43.0240
I would like the last 2 columns to come below the 1st 2 column so that it will look like this
X= 17.0600 29.6780
19.0280 42.3270
23.0660 29.4160
22.7940 43.0240
How do I go about this using he reshape function?
  2 Kommentare
Dyuman Joshi
Dyuman Joshi am 4 Sep. 2022
Bearbeitet: Dyuman Joshi am 4 Sep. 2022
I don't think that is possible using reshape (alone), as you are changing the order of elements. You can use vertical concatention to get the desired result -
x=[17.0600 29.6780 23.0660 29.4160;19.0280 42.3270 22.7940 43.0240];
y=[x(:,1:2);x(:,3:4)]
y = 4×2
17.0600 29.6780 19.0280 42.3270 23.0660 29.4160 22.7940 43.0240
Leeba Ann Chacko
Leeba Ann Chacko am 4 Sep. 2022
I see. The problem is that in this example, I have only 4 columns but I have an array with several martrices that have 2 rows but different column numbers. However, for all of them, I want to rearrange the matrix the way I did in the example above.
ex. x=[1 2 4 4 5 6; 3 4 6 6 7 8; 3 4 5 6 6 7;4 5 6 8 7 8]
i.e
1 2 4 4 5 6
3 4 6 6 7 8
3 4 5 6 6 7
4 5 6 8 7 8
rearranged to
1 2
3 4
3 4
4 5
4 4
6 6
5 6
6 8
5 6
7 8
6 7
7 8
I want to write a for loop to automate this for all the matrices with different column numbers. How do I write the code without specifically indicating the column numbers like you did in your solution?

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Dyuman Joshi
Dyuman Joshi am 4 Sep. 2022
Verschoben: Walter Roberson am 5 Sep. 2022
x=[1 2 4 4 5 6; 3 4 6 6 7 8; 3 4 5 6 6 7;4 5 6 8 7 8];
y=[reshape(x(:,1:2:end),[],1) reshape(x(:,2:2:end),[],1)]
y = 12×2
1 2 3 4 3 4 4 5 4 4 6 6 5 6 6 8 5 6 7 8
  1 Kommentar
Leeba Ann Chacko
Leeba Ann Chacko am 4 Sep. 2022
Verschoben: Walter Roberson am 5 Sep. 2022
This works perfectly, thank you!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (2)

Stephen23
Stephen23 am 4 Sep. 2022
x = [1,2,4,4,5,6; 3,4,6,6,7,8; 3,4,5,6,6,7; 4,5,6,8,7,8]
x = 4×6
1 2 4 4 5 6 3 4 6 6 7 8 3 4 5 6 6 7 4 5 6 8 7 8
y = reshape(permute(reshape(x,size(x,1),2,[]),[1,3,2]),[],2)
y = 12×2
1 2 3 4 3 4 4 5 4 4 6 6 5 6 6 8 5 6 7 8

James Tursa
James Tursa am 4 Sep. 2022
One way:
[X(:,1:2);X(:,3:4)]
  2 Kommentare
Leeba Ann Chacko
Leeba Ann Chacko am 4 Sep. 2022
Is there a way to do this without specifically indicating the column numbers like you did in your solution because I have an array with mulitple matrices containing 2 rows but different column numbers each. I cannot specify the same column numbers for all of them since I want to automate it using a for loop.
James Tursa
James Tursa am 4 Sep. 2022
Bearbeitet: James Tursa am 4 Sep. 2022
To receive quality answers, it is best to describe the complete problem when first posting your question. E.g., Do you want the result to always be 2 columns? Or 1/2 the original columns? Etc.

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Matrices and Arrays finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by