How to get 10000 variable numbers between the range of 0 and 100?

6 Ansichten (letzte 30 Tage)
i want a variable array of 10000 numbers from 0 to 100.
a = -5; b = 5; varx = a + (b-a).*rand(10000,1); varX = 10.^varx;
so i want this in the above format.
can you help me out?
  4 Kommentare
Aniket Dutta
Aniket Dutta am 28 Aug. 2022
actually i want the values between 10^(-5) and 10^2.

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Star Strider
Star Strider am 27 Aug. 2022
Bearbeitet: Star Strider am 28 Aug. 2022
If you want the numers to be between and , use the logspace function, then use randperm to randomise them —
varx = logspace(-5, 5, 1E+5) % Generate Vector
varx = 1×100000
1.0e+05 * 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
varx = varx(randperm(numel(varx))) % Randomize It
varx = 1×100000
1.0e+05 * 0.0000 0.0000 0.0000 0.0000 0.0000 0.0001 0.0000 0.0000 0.0000 0.0241 0.0000 0.0002 0.0000 0.9879 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0282 0.0000 0.0000 0.0000 0.0014 0.1385 0.0000 0.0000 0.0000
Check = [min(varx) max(varx)] % Check Result
Check = 1×2
1.0e+05 * 0.0000 1.0000
log10Check = log10(Check) % Verify
log10Check = 1×2
-5 5
EDIT — (28 Aug 2022 at 2:16)
actually i want the values between 10^(-5) and 10^2.’
varx = logspace(-5, 2, 1E+5) % Generate Vector
varx = 1×100000
1.0e+00 * 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
varx = varx(randperm(numel(varx))) % Randomize It
varx = 1×100000
12.2648 28.3893 0.0239 0.0008 4.9518 2.1702 0.0146 0.8131 0.2272 0.0000 0.2467 0.4178 5.3700 9.1466 28.9484 53.1701 0.0206 0.0001 0.0094 0.0249 2.5477 41.2094 1.6019 0.3318 41.3358 0.0008 66.8018 0.0000 0.7349 18.7881
Check = [min(varx) max(varx)] % Check Result
Check = 1×2
0.0000 100.0000
log10Check = log10(Check) % Verify
log10Check = 1×2
-5 2
.

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Abderrahim. B
Abderrahim. B am 27 Aug. 2022
Verschoben: Image Analyst am 27 Aug. 2022
Try this --
varx = 100*rand(10000, 1) ;
min(varx)
ans = 0.0227
max(varx)
ans = 99.9844

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