Delete rows in struct based on number of elements in field

1 Ansicht (letzte 30 Tage)
DavidL88
DavidL88 am 22 Aug. 2022
Kommentiert: Rik am 22 Aug. 2022
I have a 1x68 struct with 7 fields - Scouts. I want to delete rows where the number of elements under a field 'Vertices' is less than 20. How do I do this? I tried;
Scouts.Vertices(numel(Scouts.Vertices<20)) = []
but got Error using < Too many input arguments.
I would prefer not to run a loop.
Also tried this but comes back as rows = []
[rows,~] = find(numel(Scouts.Vertices)>10);
  2 Kommentare
Stephen23
Stephen23 am 22 Aug. 2022
"I have a 1x68 struct with 7 fields - Scouts. I want to delete rows ..."
Your structure only has one row.
DavidL88
DavidL88 am 22 Aug. 2022
I mean the columns (1 - 68).

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Rik
Rik am 22 Aug. 2022
If you mean you want to remove elements from your struct, you're fairly close already. Scouts.Vertices returns a comma separated list. You need to feed that to a function that will capture the output.
You could do this:
tmp={Scouts.Vertices};
tmp=cellfun('prodofsize',tmp);
ind = find(tmp>10);
But using a loop would be much simpler.
You could also use structfun, but that would only hide the loop and increase complexity as well.
  2 Kommentare
Stephen23
Stephen23 am 22 Aug. 2022
Bearbeitet: Stephen23 am 22 Aug. 2022
"You could also use structfun, but that would only hide the loop..."
It would not even hide the loop: STRUCTFUN only operates on scalar structures:
S = struct('A',{1,2,3});
structfun(@sqrt,S)
Error using structfun
Inputs to STRUCTFUN must be scalar structures.
Rik
Rik am 22 Aug. 2022
I may have been thinking of arrayfun. I don't believe I have used either of them recently. I don't think I have ever used arrayfun, other than in proving it's slower than a loop. But thank you for the correction.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Structures finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by