Is there a more efficient way to format my vector rather than manually change the code
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Adil Saeed
am 16 Aug. 2022
Kommentiert: Adil Saeed
am 16 Aug. 2022
T = 5400;
INT = 900;
tme = 0:INT:T;
TV = [tme(1):30:tme(2)-30, tme(2):15:tme(3)-15, tme(3):12:tme(4)-12, tme(4):2.4:tme(5)-2.4, tme(5):2.1428:tme(6)-2.1428, tme(6):2.5:tme(7)-2.5];
I have this code, however is there an easier way to code this if i want to change the values for 'T' and 'INT' to any random value, for the' TV' vector to automatically update rather than me manually put tme(1), tme(2) etc for those respective values in the 'tme' vector
2 Kommentare
Bruno Luong
am 16 Aug. 2022
Bearbeitet: Bruno Luong
am 16 Aug. 2022
Until you explain the law to obtain steps 30, 15, 12, 2.4, 2.1428, 2.5, then no you have to enter it by hand.
Akzeptierte Antwort
David Hill
am 16 Aug. 2022
TV =@(tme) [tme(1):30:tme(2)-30, tme(2):15:tme(3)-15, tme(3):12:tme(4)-12,...
tme(4):2.4:tme(5)-2.4, tme(5):2.1428:tme(6)-2.1428, tme(6):2.5:tme(7)-2.5];
tv1=TV(0:900:5400);
tv2=TV(0:500:5000);
5 Kommentare
John D'Errico
am 16 Aug. 2022
It IS (sort of) an answer to your question as posed. I (or anyone) might have been moved to answer a separate question, that was posed more accurately, OR an unaccepted and clarified question. You might even find that David then makes his answer a general solution then.
Weitere Antworten (0)
Siehe auch
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!