How can I show NaN as Error not Exist?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
This code Im using is to show the error in Trapezoidal Rule, and upon calculation, error is NaN, and I wanted to display NaN as "Error Does Not Exist". However,even this code show Error Does Not Exist, but if i change the value of (a) and (b) it still shows Error Does not Exist even the answer is not NaN. Please help.
syms x
f = 2*x^3+(3/(x^2))-(1/x); K2 = diff(f,2); der = inline(diff(f,2)); u = der(2); p = der(0);
a = 0; b = 2; n = 4;
if (u > p) K2 = u; else K2= p; end
disp('Relative Error of the Integral is;');
m = ('"ERROR DOES NOT EXIST"');
ErrorT = (K2*(b-a)^3)/(12*n^2);
ErrorT =(m(~isnan(m)));
disp(ErrorT);
1 Kommentar
Fangjun Jiang
am 11 Aug. 2022
Bearbeitet: Fangjun Jiang
am 11 Aug. 2022
Please double check to see if you have typos. The code doesn't make sense. Variable ErrorT is immediately re-assigned. Variable m is a fixed char array. no point to do m(~isnan(m))
m = ('"ERROR DOES NOT EXIST"');
ErrorT = (K2*(b-a)^3)/(12*n^2);
ErrorT =(m(~isnan(m)));
Antworten (1)
Fangjun Jiang
am 11 Aug. 2022
I guess the true intension is like the code below. If ErrorT is initially NaN, then "ERROR DOES NOT EXIST" will be displayed. If not, it will display empty, which is not as good as my recommendation.
syms x
f = 2*x^3+(3/(x^2))-(1/x); K2 = diff(f,2); der = inline(diff(f,2)); u = der(2); p = der(0);
a = 0; b = 2; n = 4;
if (u > p) K2 = u; else K2= p; end
disp('Relative Error of the Integral is;');
m = ["ERROR DOES NOT EXIST"];
ErrorT = (K2*(b-a)^3)/(12*n^2);
ErrorT =(m(isnan(ErrorT)));
disp(ErrorT);
My recommendation is below. When ErrorT is some value, it will actually display the value.
syms x
f = 2*x^3+(3/(x^2))-(1/x); K2 = diff(f,2); der = inline(diff(f,2)); u = der(2); p = der(0);
a = 0; b = 2; n = 4;
if (u > p) K2 = u; else K2= p; end
disp('Relative Error of the Integral is;');
ErrorT = (K2*(b-a)^3)/(12*n^2);
if isnan(ErrorT)
ErrorT="ERROR DOES NOT EXIST";
end
disp(ErrorT);
0 Kommentare
Siehe auch
Kategorien
Mehr zu Numbers and Precision finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!