How would I convert years to date time?

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I have many values given in years. How would I convert them to a date and time in UTC? For example, one of the values I have is 2022.1765918316. Its obviously the year 2022 and sometime in february, but how would I go about getting the exact date AND time (hours, minutes, and seconds) in UTC?

Accepted Answer

Stephen23
Stephen23 on 9 Aug 2022
Edited: Stephen23 on 9 Aug 2022
N = 2022.1765918316;
D = datetime(fix(N),1,1) + calyears([0;1]);
T = D(1) + diff(D)*mod(N,1)
T = datetime
06-Mar-2022 10:56:40

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