Using structures with Functions

I have a structure that I am using to simplify the workspace.

I have a structure called Condition defined so that I have multiple variables and each variable has an array for multiple conditions

Condition.Title(1) = {'test 1'};
Condition.Variable_a(1) = 1000
Condition.Variable_b(1) = 10

Condition.Title(2) = {'test 2'};
Condition.Variable_a(2) = 2000
Condition.Variable_b(2) = 20

such that

Condition =

Title: {'test 1' 'test 2'}

Variable_a: [1000 2000

Variable_b: [10 20]

I want to feed all the variables of a single condition into a function so I tried using this

Condition(1)

I hoped this would give me Title(1), Variable_a(1), and Variable_b(1) but it just gives me the entire stucture as if I had no index.

There are a number of variables so I don't want to enter each variable individually if I can avoid it

Is there a way to call all of the variables into a function with only a single column from the arrays?

Answer 1

[Stephen23]

Rather than defining a scalar structure containing arrays, it looks like you should be using a non-scalar structure:

https://www.mathworks.com/help/matlab/matlab_prog/access-multiple-elements-of-a-nonscalar-struct-array.html

For example:

Condition(1).Title = 'test 1';
Condition(1).Variable_a = 1000;
Condition(1).Variable_b = 10;
Condition(2).Title = 'test 2';
Condition(2).Variable_a = 2000;
Condition(2).Variable_b = 20;

Condition(1)

ans = struct with fields:
         Title: 'test 1'
    Variable_a: 1000
    Variable_b: 10

Condition(2)

ans = struct with fields:
         Title: 'test 2'
    Variable_a: 2000
    Variable_b: 20

Note that you can use comma-separated lists to obtain and assign data to the structure:

https://www.mathworks.com/matlabcentral/answers/1656435-tutorial-comma-separated-lists-and-how-to-use-them

[Jeremy Mercer]

Thanks I didn't understand the difference between the two input method. This may work for me but I did have it in that form earlier and ran into issues. I'll have to reassess what that issue was and see if I can work around it as I believe a non-scaler structure will be easier to deal with.

Answer 2

[Matt J]

@Stephen23's answer might be what you are looking for, but if you need the struct in scalar form for some reason, then the attached utility will split the fields for one-time purposes.

Condition.Title(1) = {'test 1'};
Condition.Variable_a(1) = 1000;
Condition.Variable_b(1) = 10;

Condition.Title(2) = {'test 2'};
Condition.Variable_a(2) = 2000;
Condition.Variable_b(2) = 20;


ConditionArray=arrayify_struct(Condition);

ConditionArray(1)

ans = struct with fields:
         Title: {'test 1'}
    Variable_a: 1000
    Variable_b: 10

ConditionArray(2)

ans = struct with fields:
         Title: {'test 2'}
    Variable_a: 2000
    Variable_b: 20