Reading numbers from String

Hello,

I have the following string

str = {'SRm40_' 'SRp5_'}

I want to read the numbers from str and include the m for a minus.

my desired Output would look like this

numbers = [-40 5]

I have tried the sscanf and regexp function but i dont seem to get it working

sscanf returns this

[numbers,~,err] = sscanf(string(str(1)),'%*5d')

err = 'Matching failure in format.'

So it cant read the the string because the first location has the 'E'.

If someone has a idea how to solve this, dont hesitate to answer :)

Have a great day

[Andrew McCauley]

This works for me:

str = {'SRm40_' 'SRp5_'};

number1 = str2num(str{1}(4:end-1));

if strcmp(str{1}(3), 'm')

number1=-number1;

end

number2 = str2num(str{2}(4:end-1));

if strcmp(str{2}(3), 'm')

number2=-number2;

end

numbers=[number1 number2];

[Andrew McCauley]

(and if it's much more than two numbers, it won't be hard to turn into a loop)

[Andrew McCauley]

In loop form in case needed:

str = {'SRm40_' 'SRp5_'};
numbers = zeros(1, length(str));
for countString = 1:length(str)
    numbers(countString) = str2num(str{countString}(4:end-1));
    if strcmp(str{countString}(3), 'm')
        numbers(countString)=-numbers(countString);
    end
end

[Lukas Ehrler]

thanks a lot for the quick answer!!

Answer 1

[Stephen23]

Another approach:

str = {'SRm40_','SRp5_'};
vec = str2double(regexprep(str,{'[A-Z_]+','m','p'},{'','-','+'}))

vec = 1×2

-40 5

Answer 2

[Steven Lord]

Yet another approach:

str = {'SRm40_','SRp5_'};
str = replace(str, 'm', '-'); % Handle negative numbers
str = replace(str, 'p', '+'); % Handle positive numbers
d = cellfun(@(x) sscanf(x, 'SR%d_'), str) % sscanf requires its first input to be scalar

d = 1×2

-40 5