how to convert hours to 'yyyy-MM-dd hh:mm:ss' format?

I have time in hours from 0-72 hours (i.e. 0, 1, 2, 3,..., 72). i.e. a = 0:72;
I would like to convert this hours into datestr with 'yyyy-MM-dd hh:mm:ss' format.
I know initial yyyy-MM-dd i.e. 2012-04-24.
So how can i set my output in 'yyyy-MM-dd hh:mm:ss' format?
I want o/p to be like;
2012-04-24 00:00:00, 2012-04-24 01:00:00, ...., 2012-04-25 00:00:00, 2012-04-25 01:00:00, ...., 2012-04-26 00:00:00, 2012-04-26 01:00:00
date should change with each 24 hours.
Any help will be greatly appriciated.

 Akzeptierte Antwort

dtm = datetime(2012,4,24,'Format','yyyy-MM-dd HH:mm:ss') + hours(0:72).'
dtm = 73×1 datetime array
2012-04-24 00:00:00 2012-04-24 01:00:00 2012-04-24 02:00:00 2012-04-24 03:00:00 2012-04-24 04:00:00 2012-04-24 05:00:00 2012-04-24 06:00:00 2012-04-24 07:00:00 2012-04-24 08:00:00 2012-04-24 09:00:00 2012-04-24 10:00:00 2012-04-24 11:00:00 2012-04-24 12:00:00 2012-04-24 13:00:00 2012-04-24 14:00:00 2012-04-24 15:00:00 2012-04-24 16:00:00 2012-04-24 17:00:00 2012-04-24 18:00:00 2012-04-24 19:00:00 2012-04-24 20:00:00 2012-04-24 21:00:00 2012-04-24 22:00:00 2012-04-24 23:00:00 2012-04-25 00:00:00 2012-04-25 01:00:00 2012-04-25 02:00:00 2012-04-25 03:00:00 2012-04-25 04:00:00 2012-04-25 05:00:00

4 Kommentare

MP
MP am 15 Jul. 2022
Bearbeitet: MP am 15 Jul. 2022
Thank you so much for your efforts.
This is datetime array. Could you please tell me how to get a string. I want to put xticklabels.
"something like datestr"
MP
MP am 15 Jul. 2022
Ok I got it
b = char(dtm); will get me desired output.
Thanks a lot.
Stephen23
Stephen23 am 15 Jul. 2022
Bearbeitet: Stephen23 am 15 Jul. 2022
str = string(dtm) % string array
txt = cellstr(dtm) % cell array of character vectors
I want to put xticklabels.
If you're plotting using this datetime data as one of the inputs in your call to plot, the tick labels will automatically be generated from the plotted datetime array. You don't need to convert to a string array in this case.
v = 0:10;
x = datetime('today') + days(v);
y = v.^2;
plot(x, y)

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MP
MP am 15 Jul. 2022

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Yes, that did a great help.... :)
Thank you so much @Stephen23

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