How can I fit a function that takes a range of x as input instead of just one value?

I have a set of measured data and a function that can be used to simulate that data (found online on a publication). The problem is that the function takes a range of x such as 40:0.01:50 as input, as well as some other parameters. I tried to use the fit function, but since it evaluates the function at each x, it doesn't work since I get the error of "Not enough input arguments". I wanted to use the fit function as it is simple to introduce ranges for the fitting parameters that I want to use with lower and upper. Is there any other way to do this or a solution?

[Torsten]

The problem is that the function takes a range of x such as 40:0.01:50 as input

Not clear what you mean here.

[David]

To use the function you have to give it a range of x, not just one value, it does not work with one value of x alone.

[Torsten]

We cannot give advice with the information given.

The usual fit functions use one input for x and parameters to produce one output y. That's what all optimization routines of MATLAB are based on.

Why does the function need a range of x-values as input to produce one (?) output y ?

[David]

It doesn't need a range of x to produce only one y, if you input a vector x, the output y is the same length.

https://doi.org/10.1107/S1600576716018379 This is the link to the publication which includes the code in the supplementary material. I certainly lack in my Matlab knowledge, and I cannot completely understand why it needs a range of x instead of using just one value. I am also attaching the code I've written (which is incomplete) and uses the functions in the publication.

Answer 1

[Image Analyst]

Just make your code prepared to handle vectors, like

x = 40:0.01:50;
y = MyFun(x)

y = 1×1001

1.0e+03 * 1.6000 1.6008 1.6016 1.6024 1.6032 1.6040 1.6048 1.6056 1.6064 1.6072 1.6080 1.6088 1.6096 1.6104 1.6112 1.6120 1.6128 1.6136 1.6144 1.6152 1.6160 1.6168 1.6176 1.6185 1.6193 1.6201 1.6209 1.6217 1.6225 1.6233

function y = MyFun(x)
y = x .^ 2;
end

[David]

My code takes vectors, the problem is that, from what I'm understanding, the "fit" function does not use the whole x vector I provide at once, and instead evaluates the function at each x independently, which doesn't work fot the code I am using.