converting csv timestamp to datetime on import

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Russell Mott
Russell Mott am 28 Jun. 2022
Kommentiert: Stephen23 am 29 Jun. 2022
I have a CSV that has two columns, Date and Time. The general format of the text is colum 1, Date, is m/DD/YYYY, and column2, Time, is HH:mm:ss SSS. However, the output device outputs the text for time omitting the zero in cases where the digit is not bordered by other numbers in its value category. For example, one case reads out:
HH:m:ss S (11:1:30 1)
when it should read HH:mm:ss SSS (11:01:30 001) if it generated equal length strings.
I cannot change the output device to correct this to always include 'HH:mm:ss SSS' to perform a simple string input to use in the datetime(DateStrings,'InputFormat',infmt) method as the string changes length.

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Stephen23
Stephen23 am 28 Jun. 2022
type test.csv
6/28/2022,11:1:30 1 06/28/2022,11:01:30 001
T = readtable('test.csv','Format','%{M/d/y}D%T%d','Delimiter',{',',' '})
T = 2×3 table
Var1 Var2 Var3 _________ ________ ____ 6/28/2022 11:01:30 1 6/28/2022 11:01:30 1
D = T.Var1 + T.Var2 + milliseconds(T.Var3);
D.Format = 'yyyy-MM-dd HH:mm:ss.SSS'
D = 2×1 datetime array
2022-06-28 11:01:30.001 2022-06-28 11:01:30.001
  2 Kommentare
Russell Mott
Russell Mott am 28 Jun. 2022
Thank you for that answer. in the read table function, I see some guidance on how the 'Format' name value pair works, but it doesnt seem like a complete guide. do you have any links to resources to understand the full functionality of the 'Format' option?
Stephen23
Stephen23 am 29 Jun. 2022
The READTABLE documentation states for the FORMAT that "The conversion specifiers are the same as the specifiers accepted by the textscan function", so this would be the resource to read:

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