Variable Number of Arguments

following is a function which unable to run in my matlab. Kindly repair the problem and tell me.

function out = print_num(format, varagin)
out = ' ' ;
argindex = 1;
skip = false;
for ii = 1: length(format)
    if skip
        skip = false;
    else
        if format(ii) ~= '%'
            out(end+1) =  format(ii);
        else
            if ii + 1> length(format)
                break;
            end
            if format(ii+1) =='%'
                out(end+1) ='%';
            else 
                if argindex >= nargin
                    error(' not enough input arguments');
                end
                out = [ out num2str(varagin{argindex},format(ii:ii+1))];
                argindex = argindex +1;
            end
            skip = true;
        end
    end
end
end
                

[Image Analyst]

What problem? You forgot to tell us what the problem is.

Don't call your variable "format" since that's a built-in function and can't be used as a variable name. Call it "userFormat" or something else.

And you also forgot to tell us how you called the function. How many arguments did you pass in and what were they? If you pass in, say 8 arguments, how do you parse them into separate variables? Are you expecting variables in a certain order?

If you have any more questions, then attach your data and code to read it in with the paperclip icon after you read this:

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Answer 1

[Walter Roberson]

The special keyword is varargin not varagin