how can I increase the size of an incremental vector filling the space with zeros

Hi, I have an incremental vector of lenght 5

a = [1 5 8 11 14]

I want to stretch a and create a new vector of length 14 in which all the empty positions between the values of a are replaced by zeros

b = [1 0 0 0 5 0 0 8 0 0 11 0 0 14]

I have already tried interpolation but doesn't seem to work

Any suggestion is very much appreciated

Answer 1

[Abolfazl Chaman Motlagh]

use ismember function.

X = cumsum(randi(3,1,5))

X = 1×5

1 3 5 7 10

Y = 1:X(end);
Y = ismember(Y,X).*Y

Y = 1×10

1 0 3 0 5 0 7 0 0 10

[Sarah Boukarras]

Yes, that worked. Thanks a lot!!

Answer 2

[Image Analyst]

The accepted answer might work but I think it's complicated and the simpler answer is to just do this:

a = [1 5 8 11 14];
b(a) = a

b = 1×14

1 0 0 0 5 0 0 8 0 0 11 0 0 14

I mean, how much simpler could it be? If you like my answer, you can vote for it.