Integration approximation with function handle
17 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Hi, i am having issues with a problem at school.
The assignment is to approximate an integral by(as i understand) looping a function for a set number of times.
Also this function needs to be called upon by a separate script.
I can't get my head around the problem so any help would be gratefully accepted.
The problem:
"" Design a function that approximates integrals with the following formula:

Where h = (b-a)/h. The input parameters must be, a, b, n and an anonymous function (a handle) for f
The only built-in features that can be used are linspace and sum.
Also design a script that calls the function and uses the call to calculate the error
i.e. the (nearest value -the exact value) if a = pi/ 2, b=pi, n=15 and f(x) = xsinx.
The exact the value must be calculated by yourself with partial integration. ""
I have done the hand calculations which results in pi-1
Code1:
I=integralapprox(pi/2,pi,15,@(x) x*sin(x));
E = pi-1;
S = I-E;
Code2:
function I=integralapprox(a,b,n,f0)
h = (b-a)/n;
f = @(a,b,h,f0) ((a+(n-1)*h+a+n*h)/2)*f0;
N=0;
for n=1:n
F = f(a,h,n,f0);
N = N + S;
end
I=h*N;

1 Kommentar
Antworten (1)
Jan
am 17 Jun. 2022
Bearbeitet: Jan
am 17 Jun. 2022
f = @(a,b,h,f0) ((a+(n-1)*h+a+n*h)/2)*f0;
This cannot work if f0 is a function handle.
This is at least confusing:
for n=1:n
Start to write the sum again:
function S = integralapprox(a, b, n, f)
h = (b - a) / n;
S = 0;
for k = 1:n
S = S + f(???); % Use k as index, not n
end
S = h * S;
end
0 Kommentare
Siehe auch
Kategorien
Mehr zu Numerical Integration and Differentiation finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!