how do I flip ever column in a matrix without using the fliplr function?

n = randi([4,15]);

n_mat = randi ( [1,100], n, n)

this generates a matrix, and I want basically do the "fliplr" command with just operations

Answer 1

[Voss]

n = randi([4,15]);
n_mat = randi ( [1,100], n, n)

n_mat = 6×6

8 27 54 5 24 28 86 65 85 87 30 81 21 47 87 93 29 33 18 84 9 44 42 68 40 67 83 92 87 95 63 2 87 95 68 35

n_mat_flipped = n_mat(:,end:-1:1)

n_mat_flipped = 6×6

28 24 5 54 27 8 81 30 87 85 65 86 33 29 93 87 47 21 68 42 44 9 84 18 95 87 92 83 67 40 35 68 95 87 2 63

[RozuSolo]

n_mat(:,end:-1:1)

is(entire row, end column : order -1 : to the first element?)

[Voss]

Precisely! ( -1 to go in reverse)

[Image Analyst]

No. Colon : means "All rows" rather than an entire row. So it's reversing each and every row, putting the last column first, then the next to the last column, and finally on the right edge it will be the original first element in the row. Again that's done for all rows so all columns are flipped left to right..