Evaluating a function with Matlab
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Danny Guana
am 18 Mai 2022
Kommentiert: Danny Guana
am 18 Mai 2022
Hello friends,
Can anyone help me figure out why I am getting an imaginary number in the following code:
I am supposed to get 1.36. I have done the same calculation using my scientific calculator and symbolab and cannot find what the error is in my code.
1 Kommentar
KSSV
am 18 Mai 2022
t = 10 ;
f = -((t-16.82)/5.604)^1.576
The result is clear, you are taking exponent of a negative number.
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Stephen23
am 18 Mai 2022
Bearbeitet: Stephen23
am 18 Mai 2022
"Can anyone help me figure out why I am getting an imaginary number in the following code:"
Because you are taking the power of a negative number.
"I am supposed to get 1.36."
The simple, effiicient, MATLAB approach is to use REALPOW:
t = 10 ;
f = realpow(-((t-16.82)/5.604),1.576)
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