For loop and omitting every 10th step

Hello,
I am doing some Bayesian by running a Gibbs sampler. My issue is that I would like to omit (drop) the draws I get in every 10th repetition. So I was wondering whether there is any command or trick while I am using the FOR command, to ignore or jump the every 10th repetition. So for example:
for i=1:30
I would i to take values 1 2 3 4 5 6 7 8 9 11 12 13 14 15 16 17 18 19 21 22 23 24 25 26 27 28 29
Any idea? Many thanks

1 Kommentar

Stephen23
Stephen23 am 20 Jan. 2015
You should not use i or j as the loop variable name, as these are the names of the inbuilt imaginary unit .

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 Akzeptierte Antwort

Image Analyst
Image Analyst am 20 Jan. 2015

0 Stimmen

for i = 1 : 30
if rem(i, 10) == 0
continue;
end
end

6 Kommentare

Yet another way:
indexesToUse = [1 2 3 4 5 6 7 8 9 11 12 13 14 15 16 17 18 19 21 22 23 24 25 26 27 28 29]
for i = indexesToUse
fprintf('i = %d\n', i);
end
Panty
Panty am 20 Jan. 2015
Clever answer..Thanks you very much 'Image'
Panty
Panty am 20 Jan. 2015
Image, Inside my initial 'for' command I have other loops and calculations. How should I write the above trick, so that any time i=10,20,30 everything that is inside my 'for' loop be ignored.
Image Analyst
Image Analyst am 20 Jan. 2015
Either of those methods will work. The first one goes through all i but then skips to the end if it hits 10, 20, 30. Put your code after the if block. The second code never even takes on the values 10, 20, 30 so there is no problem, just put your code inside the loop.
So if I do it like:
for i = 1 : 30
if rem(i, 10) == 0
continue;
end
for p=1:10
....
end
k=k+1
end
So if i=10,20 or 30 then neither "for p=1:10" nor "k=k+1" will execute. Correct?
Image Analyst
Image Analyst am 20 Jan. 2015
Correct.

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Weitere Antworten (2)

David Young
David Young am 20 Jan. 2015

1 Stimme

for i = floor(1:10/9:30)
...
end

2 Kommentare

Panty
Panty am 20 Jan. 2015
Thank you very much David for the help. It seems clever as well.
Stephen23
Stephen23 am 20 Jan. 2015
Bearbeitet: Stephen23 am 20 Jan. 2015
Do not use i as the loop variable name, as this is the name of the inbuilt imaginary unit .

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Stephen23
Stephen23 am 20 Jan. 2015

0 Stimmen

A = 1:30;
A(10:10:end) = [];
for a = A
....
end

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