Let
A = [1 2 5 4 3];
B = [ 2 5 1];
AA = A;
for i = 1:numel(B)
AA([i B(i)]) = AA([B(i) i])
end
Is there reverse way i.e, from the output AA can I get initial input A?

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Jan
Jan am 7 Apr. 2022

1 Stimme

A = [1 2 5 4 3];
B = [2 5 1];
AA = A;
for i = 1:numel(B)
AA([i, B(i)]) = AA([B(i), i]);
end
AA
AA = 1×5
5 3 2 4 1
for i = numel(B):-1:1
AA([i, B(i)]) = AA([B(i), i]);
end
AA
AA = 1×5
1 2 5 4 3

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