If condition: "in each row of a matrix one element is zero and the other one is not zero"
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How can I write the
if condition
in a more compact way than
if size(find(sum(A==0,2)==1),1) == size(A,1)
to express that "in each row of my matrix one element is zero and the other one is not zero" ?
Here an example:
clc;
A = [ 1 0
0 9
12 0
0 2
0 3]
if size(find(sum(A==0,2)==1),1) == size(A,1)
disp('in each row one element is zero and the other one is not zero')
end
0 Kommentare
Akzeptierte Antwort
Voss
am 29 Mär. 2022
You can use all()
A = [ 1 0
0 9
12 0
0 2
0 3];
if all(sum(A==0,2) == 1)
disp('in each row one element is zero and the other one is not zero')
end
2 Kommentare
Weitere Antworten (2)
Stephen23
am 29 Mär. 2022
Bearbeitet: Stephen23
am 29 Mär. 2022
A = [1,0;0,9;12,0;0,2;0,3]
if any(A,2)&any(~A,2)
disp('in each row one element is zero and the other one is not zero')
end
if diff(A==0,1,2) % this might be the most compact
disp('in each row one element is zero and the other one is not zero')
end
A = [1,2;0,0;12,0;0,2;0,3]
if any(A,2)&any(~A,2)
disp('in each row one element is zero and the other one is not zero')
else
disp('but not this one!')
end
if diff(A==0,1,2)
disp('in each row one element is zero and the other one is not zero')
else
disp('but not this one!')
end
Arif Hoq
am 29 Mär. 2022
Bearbeitet: Arif Hoq
am 29 Mär. 2022
try this
A = [ 1 0
0 9
12 0
0 2
0 3];
if nnz(A)==size(A,1)
disp('in each row one element is zero and the other one is not zero')
end
2 Kommentare
Voss
am 29 Mär. 2022
This method doesn't take into account the number of zero and non-zero elements by row, only the total:
A = [ 1 2
0 0
12 0
0 2
0 3];
if nnz(A)==size(A,1)
disp('in each row one element is zero and the other one is not zero')
end
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