calculate the number of odd fence values instead of printing them
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Shuoze Xu
am 28 Mär. 2022
Kommentiert: Shuoze Xu
am 28 Mär. 2022
Sample Output:
Given A = [ 5, 4, 6, 7, 3 ; 1, 2, 3, 4, 5 ; 5, 6, 4, 2, 4 ; 4, 5, 3, 2, 1]
% output demo
There are 9 odd values in the fence.
% This is my code
% given a matrix
A = [5,4,6,7,3;1,2,3,4,5;5,6,4,2,4;4,5,3,2,1];
% Get the number of rows and columns
[m,n] = size(A);
odd = 0;
for i = 1:m % number of rows
for j = 1:n % number of column
if (mod(A(i),2)~= 0) % if the element is not equal to zero, this is odd values
odd = odd + 1;
end
end
end
fprintf("There are %d odd values in the fence",odd);
There are 9 odd values
but in my code, it is shows There are 15 odd values in the fence.
How to improve this code?
Akzeptierte Antwort
Voss
am 28 Mär. 2022
if (mod(A(i,j),2)~= 0)
Use A(i,j) instead of A(i)
4 Kommentare
Image Analyst
am 28 Mär. 2022
And why do you say there are 9 values? My code below shows there are 10 values. Why do we disagree? Which one did I count that you say should not be counted?
Weitere Antworten (1)
Image Analyst
am 28 Mär. 2022
A = [ 5, 4, 6, 7, 3 ; 1, 2, 3, 4, 5 ; 5, 6, 4, 2, 4 ; 4, 5, 3, 2, 1]
numOddNumbers = nnz(rem(A, 2))
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