how do xor to cell array1*1?
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X=
1×1 cell array
{'10000000'}
Y=
1×1 cell array
{'01000000'}
Z=xor(X,Y)
Z={'11000000'}
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DGM
am 27 Mär. 2022
Bearbeitet: DGM
am 27 Mär. 2022
Here's one way:
% binary as cellchar
X = {'10000000'};
Y = {'01000000'};
% convert to actual logical arrays
X = X{:}=='1';
Y = Y{:}=='1';
% do a thing
Z = xor(X,Y)
% convert back to cellchar i guess
map = '01';
Z = {map(Z+1)}
If you expect the answer you show, use
Z = ~xor(X,Y)
instead for XNOR
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Image Analyst
am 27 Mär. 2022
Try this:
X = {'10000000'};
Y = {'01000000'};
Z = bitxor(bin2dec(X{1}), bin2dec(Y{1})) % A decimal number.
% Convert to binary digits.
Z = dec2bin(Z) % Correct
% Poster say the answer should be:
Z={'00111111'} % ? Huh?
I'm not sure you understand the concept of XOR. It's one, or the other, but not both. So where both bits match up the output is zero and where they are different it's one.
You can put Z into a cell if you want
Z = {dec2bin(Z)}
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