How to replace zeros in a vector with random segments of the same vector?

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I have a vector with 240000 data points. There are several, 72 elements long segments of zero values in that vector. Now I would like to replace these segments of zeros with random 72 elements long segments from the remaining non zero part of the vector.
Can you help me how can I do it?

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Image Analyst
Image Analyst am 24 Mär. 2022
Try this:
% First we need to create the data since the original poster forgot to attach it for us.
% Make random vector with values in the 1-9 range.
v = randi(9, 1, 24000);
% Make 20 stretches of 72 zeros.
startingIndexes = sort(randi(length(v), 1, 20))
for k = 1 : length(startingIndexes)
v(startingIndexes(k) : startingIndexes(k) + 71) = 0;
end
% Now we have our vector and we can begin.
%---------------------------------------------------------------------------------
% First find out what the non-zero values are
% that we can use to plug the regions of zeros.
% tic; % Start timer
availableToUse = unique(nonzeros(v));
% Now plug the zeros with numbers randomly chosen from availableToUse
for k = 1 : length(v)
if v(k) == 0
% It's zero so replace it with a random number chosen from availableToUse.
randomIndex = randi(length(availableToUse), 1, 1);
v(k) = availableToUse(randomIndex);
end
end
% toc % End timer
Time to execute is 0.002 seconds (2 milliseconds).
  1 Kommentar
Bence Laczó
Bence Laczó am 25 Mär. 2022
Bearbeitet: Bence Laczó am 25 Mär. 2022
Thank you very much for the help! I'm really appreciate your kindness!
I think I was not precise when I described my problem. I have to replace the 72 elements long segments of zeros, with random, but existing 72 elements long segments of the remaining data. So not with random single numbers, but with 72 consecutive numbers.
Now I have attached the original data.

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Weitere Antworten (1)

Arif Hoq
Arif Hoq am 24 Mär. 2022
try this:
A=[1 2 3 0 0 0 4 5 0 0 0 0 0 0 0 0 8 9]'; % any matrix
B=A(A==0); % extract the number of 0
rdnumber=randi([10 20],size(A,2),numel(B)); % generating random number
A(A==0)=rdnumber % replace with random number
A = 18×1
1 2 3 14 14 18 4 5 19 17
  1 Kommentar
Image Analyst
Image Analyst am 24 Mär. 2022
That is not using only the non-zero values to plug the zeros, like I do in my answer. You're including numbers not in the original vector.

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