loop for exctracting daily data for january, february, december,
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Muhammad Uswah Pawara
am 24 Mär. 2022
Kommentiert: Stephen23
am 24 Mär. 2022
I have 3 dimensional data (10x10x25933), it is hourly data from 1950-1-1 to 2020-12-31. how to make a loop to extract daily data for January, February, and december.
Here is my code for 1 grid point;
t1=(datetime(1950,1,1):hours(24):datetime(2020,12,31))';
t1.Format = 'yyyy-MM-dd hh:mm:ss';
TT=timetable(t1,T);
RT = ismember(month(TT.t1),[1,2,12]);
TTT = TT(RT,:);
Tdjf=TTT.T(TTT.t1);
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https://drive.google.com/file/d/1YrF2aKAxp7mym5fXJyctQW44058pfBtE/view?usp=sharing
1 Kommentar
Stephen23
am 24 Mär. 2022
Your original approach was much better than using deprecated date functions. Do NOT use DATEVEC.
DT = datetime(1950,1,1):caldays(1):datetime(2020,12,31);
DT = DT(:)
DT.Month % easiest and most efficient
for example:
idx = ismember(DT.Month,[1,2,12]);
It is not clear from your question if you expect to get three groups (one for each of the requested months), or one group containing all of the data for all of the requested months. Please clarify.
Akzeptierte Antwort
KSSV
am 24 Mär. 2022
t1=(datetime(1950,1,1):hours(24):datetime(2020,12,31))';
t1.Format = 'yyyy-MM-dd hh:mm:ss';
[y,m,d,H,M,S] = datevec(t1) ; % this will give year, monthm day, hour, minute, second
% extract january
idx = m==1 ; % Jan is month = 1
iwant = data(:,:,idx) ; % where data is your 10x10x25933 matrix
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