Impossible to print *really* vector plots when containing a lot of data
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Hi all!
So, as in the title, my general problem is that, when a plot to-be printed contains really a lot of data (e.g. many thousands of scatter points, or maybe a surface plot with high 2D data resolution) I am not able to print it as a real vector picture with the print command, even if I ask to save it in .eps or .pdf formats.
Experience tells me that it's something that really has to do with the "quantity" of data to be plotted. Look at the plots that I attached here in the .zip.
The first example is a scatter plot: very few points, plot correctly printed as a vector .eps. Using exactly the same code and only adding much more points (the smaller ones, like many thousands), the printed .eps is not vector anymore.
The second example is a 2D plot: only few simple lines, plot correctly printed as a vector .eps. Using exactly the same code and only adding on top a surface plot with quite high resolution (like 600x1200), the printed .eps is not vector anymore.
To me it really seems that the problem is in the printing, not in any other parts of the code. And I don't really understand why, it's just terribly annoying. A partial solution is to call figure.Renderer = 'Painters', and then adding a very high resolution in the print function (like '-r600' or '-r800'). But this does not really solve the problem as it just gives me a raster picture with high resolution (which consequently also tends to be quite heavy).
As simple as it is, I want such plots even with many data points to be really vector.
Any ideas? (Using MATLAB R2021b, but issue present also with previous versions)
5 Kommentare
Simon Chan
am 17 Mär. 2022
Did you try to use function exportgraphics?
Antonello Zito
am 17 Mär. 2022
Bearbeitet: Antonello Zito
am 17 Mär. 2022
Simon Chan
am 17 Mär. 2022
Just do a simple test and please find the attached zip file containing two figures.
The quality is better with additional argument ContentType set to 'vector'.
[X,Y,Z] = peaks(25);
CO(:,:,1) = zeros(25); % red
CO(:,:,2) = ones(25).*linspace(0.5,0.6,25); % green
CO(:,:,3) = ones(25).*linspace(0,1,25); % blue
surf(X,Y,Z,CO);
f = gcf;
exportgraphics(f,'default.eps'); % Pixel like
exportgraphics(f,'vector.eps','ContentType','vector'); % Better quality
Antonello Zito
am 17 Mär. 2022
Jan
am 18 Mär. 2022
Alternative, as mentioned in my answer:
exportgraphics(f, 'default.eps'); % Pixel like
f.Renderer = 'painters'
exportgraphics(f, 'vector.eps'); % Better quality
I assume, this does the same internally.
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