Error using inline/subsref (line 12) Not enough inputs to inline function.

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Hi, I've been tested so many times and tried all the answers from here and still not working.
if the expression is
with
m=4.541*TN*S0/T
T=1:0.1:100
TN=70
S0=0.99
integration with simpson 1/3
here my code:
clear all; clc;
f1=inline('3/2*(cos(x)^2)*exp(m*(3/2*(cos(x)^2))-1/2)*sin(x)','m','x');
f2=inline('exp(m*(3/2*(cos(x)^2)-1/2))','m','x');
T0=1;
TM=100;
dT=0.1;
TN=70;
S0=0.99;
for T=T0:dT:TM;
m=4.541*TN*S0/T;
a=0;b=pi;
c=0;d=pi;
n=100;
h=(b-a)/n;
f1a=f1(a);f1b=f1(b);
f2a=f2(a);f2b=f2(b);
jumeven=0;jumodd=0;
for i=1:n-1
p=mod(1,2);
if p==0
xi=x+i*h;
jumeven=jumeven+f(xi);
else
xi=x+i*h;
jumodd=jumodd+f(xi);
end
end
I1=(h/3)*(f1a+4*jumodd+2*jumeven+f1b);
I2=(h/3)*(f2c+4*jumodd+2*jumeven+f2d);
S=I1/I2;
S0=S;
end
disp([S' T']);
disp([S]);
plot(S,T,'ob-','linewidth',3);
grid on;
xlabel('S','fontsize',18);
ylabel('T','fontsize',18);
  4 Kommentare
Stephen23
Stephen23 am 12 Mär. 2022
Bearbeitet: Stephen23 am 12 Mär. 2022
"it's already in my lecturer's guide."
Your lecturer wrote their (mis)guide back in the dark ages. You should ask for your money back.
"And btw, any suggestion from you? I'm happy to try it"
You do what the MATLAB documentation recommends:
Walter Roberson
Walter Roberson am 12 Mär. 2022
f1 = @(m,x) 3/2*(cos(x).^2).*exp(m.*(3/2*(cos(x).^2))-1/2).*sin(x);
f2 = @(m,x) exp(m.*(3/2*(cos(x).^2)-1/2));

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KSSV
KSSV am 11 Mär. 2022
These lines:
f1a=f1(a);f1b=f1(b);
f2a=f2(a);f2b=f2(b);
Should be:
f1a=f1(m,a);f1b=f1(m,b);
f2a=f2(m,a);f2b=f2(m,b);
As the functions f1, f2 need two inputs.
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