How can I apply a logical mask to an image variable?
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dila suay
am 24 Feb. 2022
Kommentiert: Kaitlin Wang
am 24 Feb. 2022
Hello,
I am trying to apply a logical mask to an image variable, however I couldnt manage to do it so far.
I have tried
maskedRgbImage = bsxfun(@times, rgbImage, cast(mask, 'like', rgbImage));
maskedRgbImage = rgbImage.*mask
Also, I've tried to apply mask to the rgbImage.CData directly. All of them are giving me errors. What else I can try?
Thank you so much
2 Kommentare
Walter Roberson
am 24 Feb. 2022
Your rgbImage is a handle to a deleted image() object -- not an array of data.
Akzeptierte Antwort
Walter Roberson
am 24 Feb. 2022
rgb = rgbImage.CData;
maskedImage = rgb .* cast(repmat(c, [1 1 size(rgb,3)]),'like',rgb);
This cannot be an image() object unless you want to do something like
maskedRgbImage = copyobj(rgbImage, gca);
rgb = rgbImage.CData;
maskedImage.CData = rgb .* cast(repmat(c, [1 1 size(rgb,3)]),'like',rgb);
... but that would be directly on top of the old image.
2 Kommentare
Walter Roberson
am 24 Feb. 2022
rgb = rgbImage.CData;
maskedImage = rgb .* cast(repmat(mask, [1 1 size(rgb,3)]),'like',rgb);
or
maskedRgbImage = copyobj(rgbImage, gca);
rgb = rgbImage.CData;
maskedImage.CData = rgb .* cast(repmat(mask, [1 1 size(rgb,3)]),'like',rgb);
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Image Analyst
am 24 Feb. 2022
You don't need to do both of these:
maskedRgbImage = bsxfun(@times, rgbImage, cast(mask, 'like', rgbImage));
maskedRgbImage = rgbImage.*mask
All you need is the first one. Don't do the second one. It's not right and would need "fixing".
1 Kommentar
Kaitlin Wang
am 24 Feb. 2022
sir you are my hero. i have been looking at your answers for weeks and learning so much. thank you
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