A=[111111111111111111]
i want to generate A=[111111
111111
111111]
it is (3,6) matrix...I know it can be done easily through semicolon but that i dnt want because that A matrix is the output basically.
i also used reshape command but for that dimension shoud be same. i have taken just for example (3,6).actually the matrix is of (1,90) .i wangt to make it (3,30)
kindly help

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Jan
Jan am 24 Feb. 2022
Bearbeitet: Jan am 24 Feb. 2022

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X = ones(1, 90);
Y = reshape(X, 3, []); % 2nd argument is determined automatically
% The long form:
Y = reshape(X, 3, numel(X) / 3);

6 Kommentare

I have the suspicion that they need
Y = reshape(X, [], 3).'
That is, I suspect that they want row-wise answers, first 30 into the first row, second 30 into the second row, and so on.
VASUNDHARA V
VASUNDHARA V am 24 Feb. 2022
ya i want first 30 in first row ,second 30 in second row ,third 30 in third row
Jan
Jan am 24 Feb. 2022
Bearbeitet: Jan am 24 Feb. 2022
Y = reshape(X, 30, 3).'
A shorter example:
X = 1:12;
Y = reshape(X, [], 3).'
Y = 3×4
1 2 3 4 5 6 7 8 9 10 11 12
VASUNDHARA V
VASUNDHARA V am 24 Feb. 2022
ok thankyou all
Jan
Jan am 24 Feb. 2022
@VASUNDHARA V: A hint for future questions: You see, that 1:12 is a better example to demonstrate, what you want to achieve than "A=[111111111111111111]". Note that this is not even a vector, but a huge scalar.
VASUNDHARA V
VASUNDHARA V am 25 Feb. 2022
thankyou sir

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DGM
DGM am 24 Feb. 2022
I don't see why reshape() wouldn't work
A = ones(1,90);
A = reshape(A,3,30)
A = 3×30
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1

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