how to plot the equation

x(0)=1;
y(0)=0
t=1:15;
for n=1:15
    x(n+1)=(x(n-1)-y(n))/n+1;
    y(n+1)=(x(n)+y(n)-t)/n+1
    plot(t,x)
end

[shiv gaur]

x(0) is the initial value you take as x0

[Image Analyst]

Yeah, I figured that, but what I meant by my answer below is you're supposed to do

x(1) = 1;
y(1) = 0;

Answer 1

[Image Analyst]

Indexing starts at 1, not 0. Also, check your formulas - they look weird.

For example in

y(n+1)=(x(n)+y(n)-t)/n+1

you need t(n), not just t which is the entire array.

y(n+1)=(x(n)+y(n)-t(n))/n+1

[shiv gaur]

ok if plot these t vs x

[Image Analyst]

Are you sure that the current value of x (at n+1) depends on the value of x two elements earlier (at n-1) and also depends on y(n)?

[shiv gaur]

it is

[Image Analyst]

OK, so it's all working now that you're starting your vectors at index 1 instead of 0, and changed t to t(n)? If so, can you accept this answer because I pointed out the problems? If not, post your current code so we can continue to work on it. This is what I got. Let me know if it's the same as what you have.

x = zeros(1, 16);
y = zeros(1, 16);
x(1)=1;
% y(1)=0
t=1:15;
for n = 2: length(x) - 1
    fprintf('n = %d.\n', n);
    x(n+1) = (x(n-1)-y(n)) / n + 1; % Note only n is in the denominator, not (n+1)
    y(n+1) = (x(n)+y(n)-t(n)) / n + 1;
end

n = 2.
n = 3.
n = 4.
n = 5.
n = 6.
n = 7.
n = 8.
n = 9.
n = 10.
n = 11.
n = 12.
n = 13.
n = 14.
n = 15.

plot(t, x(1:end-1), 'b.-', 'LineWidth', 2, 'MarkerSize', 30);
hold on;
plot(t, y(1:end-1), 'r.-', 'LineWidth', 2, 'MarkerSize', 30);
grid on;
xlabel('t', 'FontSize', 20);
ylabel('x or y', 'FontSize', 20);
title('x or y VS. t', 'FontSize', 20);
legend('x', 'y')