how to calculate anomaly ?
12 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Hi all,
I want to extract data based on the months using this function 'monthofyear' to calculate anomalies.
The written code shows the wrong results.
Any help is appreciated
anom=[];
i=1;
for yy = 2019
ndays = eomday(yy, 1:12);
for mm = 1:12
for dd = 1:ndays(mm)
monthofy = month(datetime(yy,mm,dd),'monthofyear');
nn = norm(:,:,monthofy);
anom(:,:,i) = sez_chl - nn; %sez_chl is 3d matrix 72*46*46
i=i+1;
end
end
end
0 Kommentare
Antworten (1)
Image Analyst
am 15 Feb. 2022
There is a whole family of "outlier" functions, like rmoutliers(), etc. Look into them.
3 Kommentare
Image Analyst
am 17 Feb. 2022
Note that you forgot to read this
and attach your data, so all we can do is guess. We have not seen your time series data, sez_chl, or norm.
Siehe auch
Kategorien
Mehr zu Testing Frameworks finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!