# array operation in matlab

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ali hassan on 11 Feb 2022
Commented: Image Analyst on 13 Feb 2022
here we have a vector column 'FF_liter_ho_'.If i want to know that how many times non zero values were greater than 770 in a row.
so it happened only once in the column.

Image Analyst on 12 Feb 2022
Try this:
FF_liter_ho_ = [NaN 773.5 NaN NaN NaN NaN NaN NaN NaN 773.5, 771, 888, NaN 813, 889, 550, 345, NaN]
% Create mask of elements greater than 770
% Count how many times there are 1 or more such numbers "in a row" (consecutively).
% User says "i want to know that how many times non zero values were greater than 770 in a row."
runLengths = [props.Area]
% Find the longest run
maxRunLength = max(runLengths)
You get:
1×18 logical array
0 1 0 0 0 0 0 0 0 1 1 1 0 1 1 0 0 0
runLengths =
1 3 2
maxRunLength =
3
Note: when you said "non-zero" values, I took it to mean "both non-zero and non-nan" values, in other words, just the valid numbers.
##### 2 CommentsShowHide 1 older comment
Image Analyst on 13 Feb 2022
@ali hassan, it uses a concept called Connected Component labeling:
Basically it finds all elements that are connected together -- they have continguous pixels or elements. Then for each separate connected group it assigns a label. Then regionprops() makes the requested measurements on each labeled group and returns the measurements for all the groups as a structure array, though it can also return a table if you ask it to. For a 2-D array, the 'Area' is the number of pixels, while if the image is 1-D vector, the 'Area' measurement really is the length of the region in number of elements.

Voss on 11 Feb 2022
FF_liter_ho_ = [NaN 773.5 NaN NaN NaN NaN NaN NaN NaN 773.5];
% number of elements greater than 770:
nnz(FF_liter_ho_ > 770)
ans = 2
% or:
% number of unique elements greater than 770:
nnz(unique(FF_liter_ho_) > 770)
ans = 1
Image Analyst on 12 Feb 2022
Personally I think the regionprops() method in my Answer is more straightforward since you're using a function specifically meant for computing this, and don't have to do it yourself by manually manipulating indexes, but this method is okay if you do not have the Image Processing Toolbox.

Enrico Gambini on 11 Feb 2022
sum(Table.FF_liter_ho_>770)

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