matrix manipulation

1 Ansicht (letzte 30 Tage)
Raviteja
Raviteja am 22 Sep. 2011
>> A
A =
7 0 6
9 8 7
6 9 7
>> B
B =
3 7 0
6 0 0
1 2 8
>> C
C =
6 0 7
3 4 7
9 3 1
I need to have a matrix which have to store like this
>> Vec
Vec =
7 9 6 0 8 9 6 7 7
3 6 1 7 0 2 0 0 8
6 3 9 0 4 3 7 7 1
the above representing, each location element of all mattices are stored as coloumn.
For this I have written a code like this
>> P=reshape(A,[1 9]);
>> Q=reshape(B,[1 9]);
>> R=reshape(C,[1 9]);
>> Vec=[P;Q;R]
Is there any better way to do this?
  1 Kommentar
Jan
Jan am 22 Sep. 2011
What do you mean by "better"? Faster or nicer?

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Fangjun Jiang
Fangjun Jiang am 22 Sep. 2011
Vec=[A(:) B(:) C(:)]'
  4 Kommentare
Fangjun Jiang
Fangjun Jiang am 22 Sep. 2011
You could do that but you'll have hard time to identify the new_matrix in the for-loop because they have different name like A, B, C, etc. or in many case, people name it A1, A2, A3, etc, right? If you really have more than 100 matrices, the right solution is to do it right at the beginning. Instead of using A, B, C, you can define the variable as Vec=zeros(9, 100) and then you avoid the problem. See "How can I create variables A1, A2,...,A10 in a loop?" at http://matlab.wikia.com/wiki/FAQ
Fangjun Jiang
Fangjun Jiang am 22 Sep. 2011
@Walter, I need to learn from you how to put that hyper-link in place with the right FAQ item at the top of the page. This question has popped up twice just this morning. Right now, I made a bookmark out of your hyper-link.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by