# how to make a vector z that consists of odd-indexed entries of y (y=[100:1])?

3 views (last 30 days)
Hunter simmons on 20 Jan 2022
Edited: John D'Errico on 20 Jan 2022
y=[100:1];
>> z=

KSSV on 20 Jan 2022
Edited: KSSV on 20 Jan 2022
y = 1:2:100

John D'Errico on 20 Jan 2022
Edited: John D'Errico on 20 Jan 2022
A very confusing question. I'll take a wild guess. If this does not answer your question, then you need to be FAR more lear.
y = primes(20)
y = 1×8
2 3 5 7 11 13 17 19
Now take the elements of y with odd indexes. That is, start at index 1, then 3, then 5, then 7, etc.
z = y(1:2:end)
z = 1×4
2 5 11 17
But maybe you want to know the indexes of the elements in the arry that are odd numbers. How can I possibly know from your question?
u = find(mod(y,2) == 1)
u = 1×7
2 3 4 5 6 7 8
As you can see, all primes in that list except for the first are odd numbers.

R2021b

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