detecting elements change in an array

4 Ansichten (letzte 30 Tage)
Tariq Hammoudeh
Tariq Hammoudeh am 8 Jan. 2022
Bearbeitet: Tariq Hammoudeh am 8 Jan. 2022
I have an array of zeros:
x=zeros(1,36);
and in my program i change some elements of it to 1 using for example
x(6)=1;
Now i will turn some of those 1s to 2s, but is there a way i can say:
while all 1s didnt turn to 2s
.........
So basically i wanna keep inputting something as long as all the 1s didnt become 2s and it breaks out once all 1s became 2s

Akzeptierte Antwort

Walter Roberson
Walter Roberson am 8 Jan. 2022
while any(x==1)

Weitere Antworten (1)

Image Analyst
Image Analyst am 8 Jan. 2022
Try this:
x=zeros(1,36);
% Get 20 random indexes to turn to 1's.
indexes = sort(randperm(length(x), 20));
% Initialize by turning some of the zeros into ones.
x(indexes) = 1;
% Set up a failsafe
maxIterations = 10000; % Way more than you think it would ever need.
loopCounter = 1;
% Now loop over the 1's, turning some of them to 2's
% until all the 1's have been turned into 2.
while any(x == 1) && loopCounter < maxIterations
fprintf('Iteration #%d.\n', loopCounter)
% Get indexes that are 1.
indexes = find(x == 1)
% Pick a random one of those to turn to a 2
% or whatever method you want to use....
randomIndex = randi(length(indexes))
x(indexes(randomIndex)) = 2
loopCounter = loopCounter + 1;
end
x
fprintf('All done after %d iterations.\n', loopCounter)

Kategorien

Mehr zu Characters and Strings finden Sie in Help Center und File Exchange

Tags

Produkte


Version

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by