Splitting matrix into fixed rows and N columns

Hello,

I have a matrix 3900x3. My goal is to rearrange it every 30x3 values in order to gain a resulting matrix of 30x130. I guess it is a simple task but I am pretty new into matlab codes and could not find any tips on the internet. Hope I clearly explained the problem

[Yazan]

A 3900-by-3 matrix contains 11700 elements, but a 30-by-130 matrix has only 3900, so you can't just reshape the former to get to the latter. Explain better how to move from the first matrix to the second.

[daniele marchese]

I need to rearrange the 3900-by-3 [A B C] matrix concatenating it horizontally every 30-by-3 values.

So the resulting matrix will be 30-by [A B C A B C A B C ...] 390.

Answer 1

[Torsten]

M_new = M(1:30,:);   
For i=2:130
  M_new = horzcat(M_new, M(30*(i-1)+1:30*i,:));  % M is your original matrix (3900 x 3)
end

Answer 2

[daniele marchese]

thank you a lot! it worked well.

much appreciated