how to print randomly selected column?

this is what i have, the data is 39,18

data = readtable('playlist.xlsx');

random_column = input('Would you like to print a random column? yes, no. ', 's');

if random_column == "yes"

x = randi(size(data,1));

column = data(:,x);

fprinf(column)

elseif random_column == "no"

fprintf('thats the end')

end

Answer 1

[James Tursa]

Shouldn't that be size(data,2)?

Also, generally you should be using string comparison functions for the tests, not the == operator. E.g.,

isequal(random_column,'yes')

or

strcmpi(random_column,'yes')

[Haley Kelly]

@James Tursa

it still gives me this error

'Unrecognized function or variable 'fprinf'.'

[James Tursa]

Because you have a typo. Should be fprintf, not fprinf

Also, fprintf( ) is typically used with a format string. To just print a variable you can use disp( ).

[Image Analyst]

Or simply check if it starts with a y or Y

if startsWith(random_column, 'y', 'IgnoreCase', true)