Convert the cell array to matrix using for loop

I have a cell array that size 32*8 i want to convert to matrix, i use this code and have this problem (Unable to perform assignment because the indices on the left side are not compatible with the size of the right side) how can i solve

note: the number_of_collecting_fibers is less than 32

the code:

number_of_collecting_fibers=str2num(get(handles.numberoffibers,'string')) % the number of collecting fibers
Dataofcollectingfibers=get (handles.collectingfibersdatatable, 'data') %the data of the table
hold on;
for i=1:number_of_collecting_fibers
    for j=1:8
        Data_of_collecting_fibers(i,j) = cell2mat(Dataofcollectingfibers(i,j))
    end
end

Answer 1

[Adam Danz]

Since you're dealing with scalars, instead of this line

Data_of_collecting_fibers(i,j) = cell2mat(Dataofcollectingfibers(i,j))

you should use

Data_of_collecting_fibers(i,j) = Dataofcollectingfibers{i,j};

Now to the main problem. Some of your cells are empty. Converting them from cell to matrix results in {}-->[] which has a sizes of (0,0) yet you're trying to store them in a container of size (1,1). Matries cannot have empty values.

Solution: replace the empties with NaN values which are placeholders for empty numeric values.

Dataofcollectingfibers(cellfun('isempty',Dataofcollectingfibers)) = {NaN};

then proceed with the cell-to-mat conversion described above.

Alternatively, you could check each value individually,

for j = 1:8
    if isempty(Dataofcollectingfibers{i,j})
        Data_of_collecting_fibers(i,j) = NaN;
    else
        Data_of_collecting_fibers(i,j) = Dataofcollectingfibers{i,j};
    end
end