Is it possible to fprintf/sprintf each row of elements in a vector using loop?

I want to display the planets name and relative gravity such as: Moon gravity = 0.165 Earth gravity

One of the moderators recommended using a loop for this task. So, I'm trying to see if it's possible to write a code more effeciently using loops without having to print/display each planets one by one. Or is it not possible?

I've been playing around trying to find how to do it with no success, this is by far the closest I've gotten.

NOTE: the vectors are half than it is shown in the example

% Say for example
names = ["Earth"; "Venus"; "Mars"];
val = ["1.0000"; "0.8975"; '0.3915'];
planets = [names, val]

planets = 3×2 string array
    "Earth"    "1.0000"
    "Venus"    "0.8975"
    "Mars"     "0.3915"

% So I want to display the strings of each row together 
% I created this loop that seems way too long 
% When I used fprinf it ONLY shows the last row of strings without displaying -
% other rows
A = planets;
for B = 0:2
    C = A(B + 1);
    D = C';
    E = append(C, " gravity = ");
    F = [E(:,1)];
end
for G = 4:6
    H = A(G);
    I = append(H, " Earth gravity");
    J = [I(:,1)];
end
fprintf('Grav. Acce.: ');

Grav. Acce.: 

fprintf('%s ', F(:,1));

Mars gravity =  

fprintf('%s \n', J(:,1));

0.3915 Earth gravity 

Answer 1

[Stephen23]

I would not use a loop:

N = ["Earth"; "Venus"; "Mars"];
V = ["1.0000"; "0.8975"; "0.3915"];
fprintf('%s %s Gravity\n', [V(:),N(:)].');

1.0000 Earth Gravity
0.8975 Venus Gravity
0.3915 Mars Gravity

[Daven Artajo]

OMG! Thank you very much. I used up way too much of my time creating a long unnecessary loop system. This was way simplier. I learned another way to use fprintf too. Cheers mate :)

I changed it up a bit to print how I needed it:

N = ["Earth"; "Venus"; "Mars"];
V = ["1.0000"; "0.8975"; '0.3915'];
fprintf('%s gravity = %s Earth gravity \n', [N(:), V(:)].');

Earth gravity = 1.0000 Earth gravity 
Venus gravity = 0.8975 Earth gravity 
Mars gravity = 0.3915 Earth gravity