I want to arrange a 1st column of a matrix in descending order an the elements in the row is going to arrange itself according to change of the row of first vector

A= [3 2; 1 4; 2 6]

Taking the first coumn of matrix as base I want to change the other elements ie.

A=[ 3 2; 2 6; 1 4]

Ie entry to the rows going to arrange itself according to the first element of first column of matrix

Answer 1

[Stephen23]

The simple MATLAB approach:

A = [3,2;1,4;2,6]

A = 3×2

3 2 1 4 2 6

B = sortrows(A,-1)

B = 3×2

3 2 2 6 1 4

Answer 2

[KSSV]

A= [3  2; 1 4; 2 6] ;
[val,idx] = sort(A(:,1),'ascend') 

val = 3×1

1 2 3

idx = 3×1

2 3 1

A = A(idx,:)

A = 3×2

1 4 2 6 3 2

[Joy Mondal]

Thank you its working