How to improve a for

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Carlos
Carlos am 11 Okt. 2014
Bearbeitet: Andrei Bobrov am 11 Okt. 2014
Hello, i want to do this operation:
f = -[Q(:,1)'*Q(:,1); Q(:,2)'*Q(:,2); Q(:,3)'*Q(:,3); Q(:,4)'*Q(:,4); Q(:,5)'*Q(:,5); Q(:,6)'*Q(:,6); Q(:,7)'*Q(:,7); Q(:,8)'*Q(:,8); Q(:,9)'*Q(:,9); Q(:,10)'*Q(:,10)];
i have thought to do this with a for
n=10;
i=1;
while i<n+1
f(i,1)=-[Q(:,i)'*Q(:,i)]; %save in columns
i=i+1;
end
but i think there must be some way to vectorize this easily. Could you help me?
Thank you.

Akzeptierte Antwort

Azzi Abdelmalek
Azzi Abdelmalek am 11 Okt. 2014

Weitere Antworten (2)

Jan
Jan am 11 Okt. 2014
The vectorization is better, but here is a cleaner and more efficient loop method:
f = zeros(10, 1); % pre-allocate!!!
for k = 1:10
f(k, 1) = -(Q(:,k)' * Q(:,k));
end
  2 Kommentare
Carlos
Carlos am 11 Okt. 2014
Thank you so much. I think that the for loop is much better than mine before. Otherwise, how is the way to make the vectorization? Is it the answer of Azzi?
Jan
Jan am 11 Okt. 2014
Yes, Carlos.

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Andrei Bobrov
Andrei Bobrov am 11 Okt. 2014
Bearbeitet: Andrei Bobrov am 11 Okt. 2014
f = -dot(Q,Q).'

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