function to increase the range of inverse sine
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The asin() function only returns values between (-pi/2, pi/2). How can I write a function to give me values between (0, 2pi)?
Antworten (3)
Walter Roberson
am 14 Sep. 2011
1 Stimme
1 Kommentar
Jan
am 14 Sep. 2011
This will solve the problem by using the MATLAB 2013a or later. Not very efficient...
the cyclist
am 14 Sep. 2011
You can force the output to be within the range (0,2pi) by applying the mod() function:
>> mod(asin(x),2*pi)
Given only one input argument, you can't infer precisely which quadrant to return. Walter's answer points to a list of requested features (specifically, more two-argument versions of inverse trig functions).
theodore panagos
am 26 Okt. 2018
Bearbeitet: Walter Roberson
am 26 Okt. 2018
0 Stimmen
You can have the asin(x,y) from 0 to 2*pi by the formula:
asin(x,y)=pi-pi/2*(1+sgn(x))*(1-sgn(y^2))-pi/4*(2+sgn(x))*sgn(y) -sgn(x*y)*asin((abs(x)-abs(y))/sqrt(2*x^2+2*y^2))
there is x=x2-x1 and y=y2-y1
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